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Rate Constant Calculations (CIE A Level Chemistry)

Revision Note

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Richard

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Richard

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Chemistry

Rate Constant Calculations

  • The rate constant (k) of a reaction can be calculated using:
    • The initial rates and the rate equation
    • The half-life

Calculating the rate constant from the initial rate

  • The reaction of calcium carbonate (CaCO3) with chloride (Cl) ions to form calcium chloride (CaCl2) will be used as an example to calculate the rate constant from the initial rate and initial concentrations
  • The reaction and rate equation are as follows:

CaCO3 (s) + 2Cl (aq) + 2H+ (aq) → CaCl2 (aq) + CO2 (g) + H2O (l)

Rate = k [CaCO3] [Cl]

  • The progress of the reaction can be followed by measuring the initial rates of the reaction using various initial concentrations of each reactant

Experimental results of concentrations & initial rates table

  [CaCO3]
(mol dm-3)
[Cl]
(mol dm-3)
[H+]
(mol dm-3)
Initial rate of reaction
(mol dm-3 s-1)
1 0.0250 0.0125 0.0125 4.38 x 10-6
2 0.0375 0.0125 0.0125 6.63 x 10-6
3 0.00625 0.0250 0.0250 2.19 x 10-6

  • To find the rate constant (k):
    • Rearrange the rate equation to find k:
    • Rate = k [CaCO3] [Cl] → kfraction numerator rate over denominator open square brackets CaCO subscript 3 close square brackets space open square brackets Cl to the power of minus close square brackets end fraction
  • Substitute the values of one of the experiments to find k:
    • For example, using the measurements from experiment 1
    • kfraction numerator 4.38 cross times 10 to the power of negative 6 end exponent over denominator open square brackets 0.0250 close square brackets space open square brackets 0.0125 close square brackets end fraction
    • k = 1.40 x 10-2 dm3 mol-1 s-1
  • The measurements from experiments 2 or 3 could also have been used to find k
    • They would also give the same result of 1.40 x 10-2 dm3 mol-1 s-1 

Calculating the rate constant from the half-life

  • The rate constant (k) can also be calculated from the half-life of a reaction
  • You are only expected to deduce k from the half-life of a first-order reaction as the calculations for second and zero-order reactions are more complicated
  • For a first-order reaction, the half-life is related to the rate constant by the following expression:

bold italic t subscript bevelled bold 1 over bold 2 end subscript bold equals fraction numerator bold 0 bold. bold 693 over denominator bold italic k end fraction

  • Rearranging the equation to find k gives:

bold italic k bold equals fraction numerator bold 0 bold. bold 693 over denominator bold t subscript bevelled bold 1 over bold 2 end subscript end fraction

  • So, for a first-order reaction such as the methyl (CH3) rearrangement in ethanenitrile (CH3CN) with a half-life of 10.0 minutes the rate constant is:
    • k equals fraction numerator 0.693 over denominator 10.0 space cross times space 60 end fraction = 1.16 x 10-3 dm3 mol-1 s-1 

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Richard

Author: Richard

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.