Pressure in a Liquid (Cambridge O Level Physics)

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Dan MG

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Pressure in Liquids

  • A fluid is either a liquid or a gas

When an object is immersed in a fluid, the fluid will exert pressure, squeezing the object

  • This pressure is exerted evenly across the whole surface of the fluid and in all directions
  • The pressure exerted on objects in fluids creates forces against surfaces
  • These forces act at 90 degrees (at right angles) to the surface

 

Pressure on an Object in a Fluid

pressure-&-force, IGCSE & GCSE Physics revision notes

The pressure of a fluid on an object creates a force normal (at right angles) to the surface

 

  • The pressure of a fluid on an object will increase with:
    • Depth within the fluid
    • Increased density of the fluid

Calculating Pressure in Liquids

  • The pressure is more accurately the difference in pressure at different depths h in a liquid, since the pressure changes with the depth

  • The pressure due to a column of liquid can be calculated using the equation

Δp = ρgΔh

  • Where:
    • Δp = change in pressure in pascals (Pa)
      • Where 1 Pa = 1 N/m2
    • ρ = density of the liquid in kilograms per metre cubed (kg/m3)
    • g = gravitational field strength on Earth in newtons per kilogram (N/kg)
    • Δh = change in height of the column in metres (m)

  • The force from the pressure is exerted evenly across the whole surface of an object in a liquid, and in all directions

Even Pressure on an Object in a Fluid

pressure-in-liquids, IGCSE & GCSE Physics revision notes

The force from the pressure of objects in a liquid is exerted evenly across its whole surface

Worked example

Calculate the depth of water in a swimming pool where a pressure of 20 kPa is exerted due to the water. The density of water is 1000 kg/m3 and the gravitational field strength on Earth is 9.8 N/kg.

Answer:

Step 1: List the known quantities, converting any units necessary:

  • Pressure due to fluid, Δp = 20 kPa = 20 000 Pa
  • Density of water, ρ = 1000 kg/m3
  • Gravitational field strength, g = 9.8 N/kg

Step 2: Rearrange the relevant equation for depth:

  • The equation for pressure in a fluid is

Δp = ρgΔh{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}

  • Rearrange for depth, Δh

Δh = Δpρg{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}

Step 3: Substitute the known quantities:

  • Depth is

Δh = 20 0001000 × 9.8{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}

Δh = 2.0408 m{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}

  • Give the answer to 2 significant figures (like the values given in the question)

Δh = 2.0 m{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}

Exam Tip

This pressure equation will be given on your formula sheet, however, make sure you are comfortable with rearranging it for the variable required in the question!

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Dan MG

Author: Dan MG

Dan graduated with a First-class Masters degree in Physics at Durham University, specialising in cell membrane biophysics. After being awarded an Institute of Physics Teacher Training Scholarship, Dan taught physics in secondary schools in the North of England before moving to SME. Here, he carries on his passion for writing enjoyable physics questions and helping young people to love physics.