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Expansion of the Octet (HL) (HL IB Chemistry)

Revision Note

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Chemistry

Expansion of the Octet

Expansion of the octet

  • Elements in period 3 and above have the possibility of having more than eight electrons in their valence shell
  • This is because there is a d-subshell present which can accommodate additional pairs of electrons
  • This is known as the expansion of the octet
  • The concept explains why structures such as PCl5 and SF6 exist, which have 5 and 6 bonding pairs of electrons respectively, around the central atom

Five electron pairs

Phosphorus pentachloride, PCl5

  • An example of a molecule with five bonding electron pairs is phosphorus pentachloride, PCl5
  • The total number of valence electrons is = P + 5Cl = 5 + (5 x 7) = 40
  • The number of bonding pairs is 5, which accounts for 10 electrons
  • The remaining 30 electrons would be 15 lone pairs, so that each Cl has 3 lone pairs
  • The completed Lewis formula looks like this:

Lewis formula of PCl5 

Lewis structure of PCl5 showing an expanded octet for phosphorous containing 10 electrons

The octet of the central phosphorous atom has been expanded to hold 10 electrons

Sulfur tetrafluoride, SF4

  • The total number of valence electrons is = S + 4F = 6 + (4 x 7) = 34
  • The number of bonding pairs is 4, which accounts for 8 electrons
  • The remaining 26 electrons would be 13 lone pairs
  • Fluorine cannot expand the octet so each fluorine would accommodate 3 lone pairs, accounting for 24 electrons, leaving 1 lone pair on the sulfur (sulfur has expanded the octet)
  • The completed Lewis formula looks like this:

Lewis formula of SF4 

Lewis structure of SF4 showing an expanded octet for sulfur containing 10 electrons

The octet of the central sulfur atom has been expanded to hold 10 electrons

Chlorine trifluoride, ClF3

  • The total number of valence electrons is = Cl + 3F = 7 + (3 x 7) = 28
  • The number of bonding pairs is 3, which accounts for 6 electrons
  • The remaining 22 electrons would be 11 lone pairs
  • Fluorine cannot expand the octet so each fluorine would accommodate 3 lone pairs, accounting for 18 electrons, leaving 2 lone pairs on the chlorine
  • The completed Lewis formula looks like this:

Lewis formula of ClF3 

Lewis structure of ClF3 showing an expanded octet for chlorine containing 10 electrons

The octet of the central chlorine atom has been expanded to hold 10 electrons

Triiodide ion, l3-

  • The total number of valence electrons is = 3I + the negative charge = (3 x 7) + 1 = 22
  • The number of bonding pairs is 2, which accounts for 4 electrons
  • The remaining 18 electrons would be 9 lone pairs
  • Iodine would accommodate 3 lone pairs, accounting for 12 electrons, leaving 3 lone pairs on the central iodine
  • The completed Lewis formula looks like this:

Lewis formula of I3 

Lewis structure of I3 showing an expanded octet for iodine containing 10 electrons

The octet of the central iodine atom has been expanded to hold 10 electrons

Six electron pairs

Sulfur hexafluoride, SF6

  • An example of a molecule with six bonding electron pairs is sulfur hexafluoride, SF6
  • The total number of valence electrons is = S + 6F = 6 + (6 x 7) = 48
  • The number of bonding pairs is 6, which accounts for 12 electrons
  • The remaining 36 electrons would be 18 lone pairs, so that each F has 3 lone pairs, accounting for all electrons and no lone pairs
  • The completed Lewis formula looks like this:

Lewis formula of SF6 

Lewis structure of SF6 showing an expanded octet for sulfur containing 12 electrons

The octet of the central sulfur atom has been expanded to hold 12 electrons

Bromine pentafluoride, BrF5

  • The total number of valence electrons is = Br + 5F = 7 + (5 x 7) = 42
  • The number of bonding pairs is 5, which accounts for 10 electrons
  • The remaining 32 electrons would be 16 lone pairs
  • Fluorine cannot expand the octet so each fluorine would accommodate 3 lone pairs, accounting for 30 electrons, leaving 1 lone pair on the bromine
  • The completed Lewis formula looks like this:

Lewis formula of BrF5 

Lewis structure of BrF5 showing an expanded octet for bromine containing 12 electrons

The octet of the central bromine atom has been expanded to hold 12 electrons

Xenon tetrafluoride, XeF4

  • The total number of valence electrons is = Xe + 4F = 8 + (4 x 7) = 36
  • The number of bonding pairs is 4, which accounts for 8 electrons
  • The remaining 28 electrons would be 14 lone pairs
  • Each fluorine would accommodate 3 lone pairs, accounting for 24 electrons, leaving 2 lone pairs on the xenon
  • The completed Lewis formula looks like this:

Lewis formula of XeF4 

Lewis structure of XeF4 showing an expanded octet for xenon containing 12 electrons

The octet of the central xenon atom has been expanded to hold 12 electrons

Revisiting Valence Shell Electron Pair Repulsion Theory (VSEPR)

  • Molecular shapes and the angles between bonds can be predicted using the three basic rules associated with valence shell electron pair repulsion theory known by the abbreviation VSEPR theory
  • VSEPR theory consists of three basic rules:
    • All electron pairs and all lone pairs arrange themselves as far apart in space as possible.
    • Lone pairs repel more strongly than bonding pairs
    • Multiple bonds behave like single bonds
  • For more information about valence shell electron pair repulsion theory, see our revision note on Shapes of Molecules

Molecular geometry versus electron domain geometry

  • It is important to distinguish between molecular geometry and electron domain geometry in exam questions
    • Molecular geometry refers to the shape of the molecules based on the relative orientation of the atoms
    • Electron domain geometry refers to the relative orientation of all the bonding and lone pairs of electrons
  • The Lewis formula for water enables us to see that there are four electron pairs around the oxygen so the electron domain geometry is tetrahedral
  • However, the molecular geometry shows us there are two angled bonds so the shape is bent, angular, bent linear or V-shaped (when viewed upside down)

Lewis formula and molecular shape of water

Diagrams showing the Lewis structure of water and corresponding structural formula of water with a bond angle of 104.5 <sup>o<sup>C

The Lewis formula of water and molecular shape can be used to determine the electron domain and molecular geometries

Five electron domains

Table of molecular geometries associated with five electron domains

Electron domain geometry Bonding pairs Lone pairs Molecular geometry Shape example
trigonal bipyramidal 5 0 trigonal bipyramidal pcl5-shape-and-angles
trigonal bipyramidal 4 1 seesaw sf4-shape-and-angles
trigonal bipyramidal 3 2 T-shape clf3-shape-and-angles
trigonal bipyramidal 2 3 Linear i3-shape-

 

  • PCl5  is a symmetrical molecule so the electron cloud charge is evenly spread
    • This means that it will be a non-polar molecule as any dipoles from the P–Cl bonds would be cancelled out
  • SF4 and ClF3 are asymmetrical molecules having one or two lone pairs on one side of the central axis making the overall molecule polar

Six electron domains

Table of molecular geometries associated with six electron domains

Electron domain geometry Bonding pairs Lone pairs Molecular geometry Shape example
octahedral 6 0 octahedral sf6-shape-
octahedral 5 1 square based pyramid brf5-shape-
octahedral 4 2 square planar xef4-shape-

 

  • SF6 is a symmetrical molecule so the electron cloud charge is evenly spread with 90o between the bonds
    • This means that it will be a non-polar molecule as any dipoles from the S–F bonds would be cancelled out
  • XeF4 is also non-polar despite having two lone pairs
    • The bonding pairs are at 90o to the plane and the lone pairs are at 180o
    • The lone pairs are arranged above and below the square plane resulting in an even distribution of electron cloud charge
  • BrF5 is asymmetrical having a lone pair at the base of the pyramid making the overall molecule polar

Worked example

What is the electron domain geometry, molecular geometry and F-Xe-F bond angle of xenon difluoride, XeF2?

Answer

  • Count the valence electrons = Xe + 2F = 8 + (2 x 7) = 22
  • There are two bonding pairs, accounting for 4 electrons, so 18 electrons remain
  • Each fluorine should have 3 lone pairs, accounting for 6 pairs or 12 electrons, which leaves 3 lone pairs on the xenon
  • Xenon, therefore, has 2 bonding pairs and 3 lone pairs meaning it has:
    • Electron domain geometry = trigonal bipyramid
    • Molecular geometry = linear
  • The bond angle will be 180o (having the same structure as the triiodide ion)

Exam Tip

Lewis structure and Lewis formula may be used interchangeably, but Lewis formula is the preferred term in the specification.

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Richard

Author: Richard

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.